Reema took 5 ml of Lead Nitrate solution
in a beaker and added approximately 4 ml
of Potassium Iodide solution to it. What
would she observe?
(a) The solution turned red.
(b) Yellow precipitate was formed.
(c) White precipitate was formed.
(d) The reaction mixture became hot.
Ans. (b) Yellow precipitate was formed.
Explanation: When potassium iodide solution
is added to lead nitrate solution, a yellow
coloured precipitate of lead iodide is formed.
Pb(NO3)2(aq) + 2KI(aq) → PbI2(s)+ 2KNO3(aq
